Base | Representation |
---|---|
bin | 100000001000010111000011… |
… | …000100000011010000100111 |
3 | 200112100021221122221122111002 |
4 | 200020113003010003100213 |
5 | 122010223424323442433 |
6 | 1220313455512503515 |
7 | 41523311613062522 |
oct | 4010270304032047 |
9 | 615307848848432 |
10 | 141311991624743 |
11 | 41032096304605 |
12 | 13a232640aab9b |
13 | 60b0881cc9484 |
14 | 26c7773313bb9 |
15 | 1150cb107a9e8 |
hex | 8085c3103427 |
141311991624743 has 2 divisors, whose sum is σ = 141311991624744. Its totient is φ = 141311991624742.
The previous prime is 141311991624721. The next prime is 141311991624751. The reversal of 141311991624743 is 347426199113141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141311991624743 - 218 = 141311991362599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141311991627743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70655995812371 + 70655995812372.
It is an arithmetic number, because the mean of its divisors is an integer number (70655995812372).
Almost surely, 2141311991624743 is an apocalyptic number.
141311991624743 is a deficient number, since it is larger than the sum of its proper divisors (1).
141311991624743 is an equidigital number, since it uses as much as digits as its factorization.
141311991624743 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3919104, while the sum is 56.
The spelling of 141311991624743 in words is "one hundred forty-one trillion, three hundred eleven billion, nine hundred ninety-one million, six hundred twenty-four thousand, seven hundred forty-three".
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