Base | Representation |
---|---|
bin | 100000001000010111000011… |
… | …100100000101101011100011 |
3 | 200112100021222020202100002112 |
4 | 200020113003210011223203 |
5 | 122010223434001221032 |
6 | 1220313500412505535 |
7 | 41523312044342153 |
oct | 4010270344055343 |
9 | 615307866670075 |
10 | 141312000023267 |
11 | 410320a0020537 |
12 | 13a23266a7b2ab |
13 | 60b088397a108 |
14 | 26c777449c763 |
15 | 1150cb1b891b2 |
hex | 8085c3905ae3 |
141312000023267 has 2 divisors, whose sum is σ = 141312000023268. Its totient is φ = 141312000023266.
The previous prime is 141312000023197. The next prime is 141312000023281. The reversal of 141312000023267 is 762320000213141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141312000023267 - 222 = 141311995828963 is a prime.
It is not a weakly prime, because it can be changed into another prime (141312000023287) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70656000011633 + 70656000011634.
It is an arithmetic number, because the mean of its divisors is an integer number (70656000011634).
Almost surely, 2141312000023267 is an apocalyptic number.
141312000023267 is a deficient number, since it is larger than the sum of its proper divisors (1).
141312000023267 is an equidigital number, since it uses as much as digits as its factorization.
141312000023267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 141312000023267 in words is "one hundred forty-one trillion, three hundred twelve billion, twenty-three thousand, two hundred sixty-seven".
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