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141312103 is a prime number
BaseRepresentation
bin10000110110001…
…00000001100111
3100211220101202121
420123010001213
5242133441403
622004450411
73334063432
oct1033040147
9324811677
10141312103
1172848969
123b3a9a07
132337963a
1414aa6819
15c6153bd
hex86c4067

141312103 has 2 divisors, whose sum is σ = 141312104. Its totient is φ = 141312102.

The previous prime is 141312097. The next prime is 141312113. The reversal of 141312103 is 301213141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141312103 - 217 = 141181031 is a prime.

It is a super-2 number, since 2×1413121032 = 39938220908565218, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141312113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70656051 + 70656052.

It is an arithmetic number, because the mean of its divisors is an integer number (70656052).

Almost surely, 2141312103 is an apocalyptic number.

141312103 is a deficient number, since it is larger than the sum of its proper divisors (1).

141312103 is an equidigital number, since it uses as much as digits as its factorization.

141312103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 141312103 is about 11887.4767297354. The cubic root of 141312103 is about 520.8665322724.

Adding to 141312103 its reverse (301213141), we get a palindrome (442525244).

The spelling of 141312103 in words is "one hundred forty-one million, three hundred twelve thousand, one hundred three".