14132043314232 has 16 divisors (see below), whose sum is σ = 35330108285640. Its totient is φ = 4710681104736.

The previous prime is 14132043314189. The next prime is 14132043314261. The reversal of 14132043314232 is 23241334023141.

It is a junction number, because it is equal to n+sod(n) for n = 14132043314193 and 14132043314202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294417569023 + ... + 294417569070.

Almost surely, 2^{14132043314232} is an apocalyptic number.

14132043314232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14132043314232 is an abundant number, since it is smaller than the sum of its proper divisors (21198064971408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14132043314232 is a wasteful number, since it uses less digits than its factorization.

14132043314232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 588835138102 (or 588835138098 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 14132043314232 its reverse (23241334023141), we get a palindrome (37373377337373).

The spelling of 14132043314232 in words is "fourteen trillion, one hundred thirty-two billion, forty-three million, three hundred fourteen thousand, two hundred thirty-two".