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141321132040122 = 23317153944588279
BaseRepresentation
bin100000001000011111100011…
…110111111101111110111010
3200112101011112200020212012000
4200020133203313331332322
5122010401134300240442
61220322010511401430
741524054252244046
oct4010374367757672
9615334480225160
10141321132040122
1141035a56890a01
1213a24b95223276
1360b16aa8a0b98
1426c7d9d23b026
151151148741d4c
hex8087e3dfdfba

141321132040122 has 32 divisors (see below), whose sum is σ = 332520310684800. Its totient is φ = 44336041424064.

The previous prime is 141321132040063. The next prime is 141321132040181. The reversal of 141321132040122 is 221040231123141.

141321132040122 is a `hidden beast` number, since 1 + 4 + 1 + 3 + 211 + 3 + 20 + 401 + 22 = 666.

It is an interprime number because it is at equal distance from previous prime (141321132040063) and next prime (141321132040181).

It is a super-2 number, since 2×1413211320401222 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76972293222 + ... + 76972295057.

It is an arithmetic number, because the mean of its divisors is an integer number (10391259708900).

Almost surely, 2141321132040122 is an apocalyptic number.

141321132040122 is an abundant number, since it is smaller than the sum of its proper divisors (191199178644678).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141321132040122 is a wasteful number, since it uses less digits than its factorization.

141321132040122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153944588307 (or 153944588301 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 141321132040122 its reverse (221040231123141), we get a palindrome (362361363163263).

The spelling of 141321132040122 in words is "one hundred forty-one trillion, three hundred twenty-one billion, one hundred thirty-two million, forty thousand, one hundred twenty-two".

Divisors: 1 2 3 6 9 17 18 27 34 51 54 102 153 306 459 918 153944588279 307889176558 461833764837 923667529674 1385501294511 2617058000743 2771002589022 4156503883533 5234116001486 7851174002229 8313007767066 15702348004458 23553522006687 47107044013374 70660566020061 141321132040122