1413231201101 has 2 divisors, whose sum is σ = 1413231201102. Its totient is φ = 1413231201100.

The previous prime is 1413231200999. The next prime is 1413231201131. The reversal of 1413231201101 is 1011021323141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 876676416100 + 536554785001 = 936310^2 + 732499^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413231201101 - 2¹⁰ = 1413231200077 is a prime.

It is a super-2 number, since 2×1413231201101² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413231201131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706615600550 + 706615600551.

It is an arithmetic number, because the mean of its divisors is an integer number (706615600551).

Almost surely, 2^{1413231201101} is an apocalyptic number.

It is an amenable number.

1413231201101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413231201101 is an equidigital number, since it uses as much as digits as its factorization.

1413231201101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1413231201101 its reverse (1011021323141), we get a palindrome (2424252524242).

The spelling of 1413231201101 in words is "one trillion, four hundred thirteen billion, two hundred thirty-one million, two hundred one thousand, one hundred one".