Base | Representation |
---|---|
bin | 1100110110100110111111… |
… | …1111110100000101101001 |
3 | 1212001000222202222200222011 |
4 | 3031221233333310011221 |
5 | 3323020443234400431 |
6 | 50020144313555521 |
7 | 2656012045621306 |
oct | 315515777640551 |
9 | 55030882880864 |
10 | 14132321403241 |
11 | 4559536004398 |
12 | 1702b31a15ba1 |
13 | 7b6897a55962 |
14 | 36c017d780ad |
15 | 19793295ecb1 |
hex | cda6fff4169 |
14132321403241 has 2 divisors, whose sum is σ = 14132321403242. Its totient is φ = 14132321403240.
The previous prime is 14132321403209. The next prime is 14132321403251. The reversal of 14132321403241 is 14230412323141.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10302848138025 + 3829473265216 = 3209805^2 + 1956904^2 .
It is a cyclic number.
It is not a de Polignac number, because 14132321403241 - 25 = 14132321403209 is a prime.
It is not a weakly prime, because it can be changed into another prime (14132321403251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066160701620 + 7066160701621.
It is an arithmetic number, because the mean of its divisors is an integer number (7066160701621).
Almost surely, 214132321403241 is an apocalyptic number.
It is an amenable number.
14132321403241 is a deficient number, since it is larger than the sum of its proper divisors (1).
14132321403241 is an equidigital number, since it uses as much as digits as its factorization.
14132321403241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 14132321403241 its reverse (14230412323141), we get a palindrome (28362733726382).
The spelling of 14132321403241 in words is "fourteen trillion, one hundred thirty-two billion, three hundred twenty-one million, four hundred three thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •