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1413236265037 is a prime number
BaseRepresentation
bin10100100100001011011…
…100100001000001001101
312000002210212100201122021
4110210023130201001031
5141123301440440122
63001122021450141
7204050212023022
oct24441334410115
95002725321567
101413236265037
114a5394035103
121a9a89b70951
13a3362c1c66c
144c5884b7549
1526b651d11c7
hex1490b72104d

1413236265037 has 2 divisors, whose sum is σ = 1413236265038. Its totient is φ = 1413236265036.

The previous prime is 1413236264987. The next prime is 1413236265053. The reversal of 1413236265037 is 7305626323141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 923724743236 + 489511521801 = 961106^2 + 699651^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413236265037 - 215 = 1413236232269 is a prime.

It is a super-2 number, since 2×14132362650372 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1413236264984 and 1413236265002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413236265937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706618132518 + 706618132519.

It is an arithmetic number, because the mean of its divisors is an integer number (706618132519).

Almost surely, 21413236265037 is an apocalyptic number.

It is an amenable number.

1413236265037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413236265037 is an equidigital number, since it uses as much as digits as its factorization.

1413236265037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320, while the sum is 43.

The spelling of 1413236265037 in words is "one trillion, four hundred thirteen billion, two hundred thirty-six million, two hundred sixty-five thousand, thirty-seven".