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1413300031143 = 37111323372112621
BaseRepresentation
bin10100100100001111001…
…111110000111010100111
312000002222022100101021220
4110210033033300322213
5141123414301444033
63001132220311423
7204051615024030
oct24441717607247
95002868311256
101413300031143
114a5417028570
121a9aa73a2573
13a33731b78a0
144c592b55a87
1526b6aac9bb3
hex1490f3f0ea7

1413300031143 has 256 divisors, whose sum is σ = 2725352275968. Its totient is φ = 627492096000.

The previous prime is 1413300031141. The next prime is 1413300031207. The reversal of 1413300031143 is 3411300033141.

It is not a de Polignac number, because 1413300031143 - 21 = 1413300031141 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413300031141) by changing a digit.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 539220373 + ... + 539222993.

It is an arithmetic number, because the mean of its divisors is an integer number (10645907328).

Almost surely, 21413300031143 is an apocalyptic number.

1413300031143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1413300031143 is a deficient number, since it is larger than the sum of its proper divisors (1312052244825).

1413300031143 is a wasteful number, since it uses less digits than its factorization.

1413300031143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2926.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 1413300031143 its reverse (3411300033141), we get a palindrome (4824600064284).

The spelling of 1413300031143 in words is "one trillion, four hundred thirteen billion, three hundred million, thirty-one thousand, one hundred forty-three".