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1413432441137 is a prime number
BaseRepresentation
bin10100100100010111001…
…000110111100100110001
312000010022112111111122202
4110210113020313210301
5141124202201104022
63001153310312545
7204055113343013
oct24442710674461
95003275444582
101413432441137
114a5484846112
121a9b237b8755
13a33947682b2
144c5a65821b3
1526b77532592
hex14917237931

1413432441137 has 2 divisors, whose sum is σ = 1413432441138. Its totient is φ = 1413432441136.

The previous prime is 1413432441101. The next prime is 1413432441151. The reversal of 1413432441137 is 7311442343141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 815546261776 + 597886179361 = 903076^2 + 773231^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413432441137 - 210 = 1413432440113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1413432441137.

It is not a weakly prime, because it can be changed into another prime (1413432441037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706716220568 + 706716220569.

It is an arithmetic number, because the mean of its divisors is an integer number (706716220569).

Almost surely, 21413432441137 is an apocalyptic number.

It is an amenable number.

1413432441137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413432441137 is an equidigital number, since it uses as much as digits as its factorization.

1413432441137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96768, while the sum is 38.

Adding to 1413432441137 its reverse (7311442343141), we get a palindrome (8724874784278).

The spelling of 1413432441137 in words is "one trillion, four hundred thirteen billion, four hundred thirty-two million, four hundred forty-one thousand, one hundred thirty-seven".