Base | Representation |
---|---|
bin | 1000001110100101000… |
… | …1000010100111010001 |
3 | 111111212002200121100111 |
4 | 2003221101002213101 |
5 | 4303442220340303 |
6 | 144534134521321 |
7 | 13132563345562 |
oct | 2035121024721 |
9 | 444762617314 |
10 | 141352511953 |
11 | 54a46898414 |
12 | 2348a806241 |
13 | 10438b54823 |
14 | 6bad0dc169 |
15 | 3a24835b6d |
hex | 20e94429d1 |
141352511953 has 2 divisors, whose sum is σ = 141352511954. Its totient is φ = 141352511952.
The previous prime is 141352511893. The next prime is 141352511977. The reversal of 141352511953 is 359115253141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129522251664 + 11830260289 = 359892^2 + 108767^2 .
It is a cyclic number.
It is not a de Polignac number, because 141352511953 - 217 = 141352380881 is a prime.
It is not a weakly prime, because it can be changed into another prime (141352511983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70676255976 + 70676255977.
It is an arithmetic number, because the mean of its divisors is an integer number (70676255977).
Almost surely, 2141352511953 is an apocalyptic number.
It is an amenable number.
141352511953 is a deficient number, since it is larger than the sum of its proper divisors (1).
141352511953 is an equidigital number, since it uses as much as digits as its factorization.
141352511953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 81000, while the sum is 40.
The spelling of 141352511953 in words is "one hundred forty-one billion, three hundred fifty-two million, five hundred eleven thousand, nine hundred fifty-three".
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