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141352511893 is a prime number
BaseRepresentation
bin1000001110100101000…
…1000010100110010101
3111111212002200121021021
42003221101002212111
54303442220340033
6144534134521141
713132563345445
oct2035121024625
9444762617237
10141352511893
1154a4689836a
122348a8061b1
1310438b547a8
146bad0dc125
153a24835b2d
hex20e9442995

141352511893 has 2 divisors, whose sum is σ = 141352511894. Its totient is φ = 141352511892.

The previous prime is 141352511887. The next prime is 141352511953. The reversal of 141352511893 is 398115253141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131462806084 + 9889705809 = 362578^2 + 99447^2 .

It is an emirp because it is prime and its reverse (398115253141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141352511893 - 29 = 141352511381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141352511843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70676255946 + 70676255947.

It is an arithmetic number, because the mean of its divisors is an integer number (70676255947).

Almost surely, 2141352511893 is an apocalyptic number.

It is an amenable number.

141352511893 is a deficient number, since it is larger than the sum of its proper divisors (1).

141352511893 is an equidigital number, since it uses as much as digits as its factorization.

141352511893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 43.

The spelling of 141352511893 in words is "one hundred forty-one billion, three hundred fifty-two million, five hundred eleven thousand, eight hundred ninety-three".