Base | Representation |
---|---|
bin | 1000001110100101000… |
… | …1000010100110010101 |
3 | 111111212002200121021021 |
4 | 2003221101002212111 |
5 | 4303442220340033 |
6 | 144534134521141 |
7 | 13132563345445 |
oct | 2035121024625 |
9 | 444762617237 |
10 | 141352511893 |
11 | 54a4689836a |
12 | 2348a8061b1 |
13 | 10438b547a8 |
14 | 6bad0dc125 |
15 | 3a24835b2d |
hex | 20e9442995 |
141352511893 has 2 divisors, whose sum is σ = 141352511894. Its totient is φ = 141352511892.
The previous prime is 141352511887. The next prime is 141352511953. The reversal of 141352511893 is 398115253141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 131462806084 + 9889705809 = 362578^2 + 99447^2 .
It is an emirp because it is prime and its reverse (398115253141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141352511893 - 29 = 141352511381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141352511843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70676255946 + 70676255947.
It is an arithmetic number, because the mean of its divisors is an integer number (70676255947).
Almost surely, 2141352511893 is an apocalyptic number.
It is an amenable number.
141352511893 is a deficient number, since it is larger than the sum of its proper divisors (1).
141352511893 is an equidigital number, since it uses as much as digits as its factorization.
141352511893 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 129600, while the sum is 43.
The spelling of 141352511893 in words is "one hundred forty-one billion, three hundred fifty-two million, five hundred eleven thousand, eight hundred ninety-three".
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