141355435451 has 2 divisors, whose sum is σ = 141355435452. Its totient is φ = 141355435450.

The previous prime is 141355435447. The next prime is 141355435453. The reversal of 141355435451 is 154534553141.

141355435451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (154534553141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141355435451 - 2² = 141355435447 is a prime.

Together with 141355435453, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 141355435399 and 141355435408.

It is not a weakly prime, because it can be changed into another prime (141355435453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70677717725 + 70677717726.

It is an arithmetic number, because the mean of its divisors is an integer number (70677717726).

Almost surely, 2^141355435451 is an apocalyptic number.

141355435451 is a deficient number, since it is larger than the sum of its proper divisors (1).

141355435451 is an equidigital number, since it uses as much as digits as its factorization.

141355435451 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 360000, while the sum is 41.

Adding to 141355435451 its reverse (154534553141), we get a palindrome (295889988592).

The spelling of 141355435451 in words is "one hundred forty-one billion, three hundred fifty-five million, four hundred thirty-five thousand, four hundred fifty-one".