Base | Representation |
---|---|
bin | 100000001001101001001000… |
… | …100101011110000110101110 |
3 | 200112122201110020220221222102 |
4 | 200021221020211132012232 |
5 | 122013144432030213402 |
6 | 1220422153511415102 |
7 | 41532552031214066 |
oct | 4011511045360656 |
9 | 615581406827872 |
10 | 141400131101102 |
11 | 41066505792755 |
12 | 13a38361984492 |
13 | 60b8c8a52a293 |
14 | 26cbb350a23a6 |
15 | 115321dde6102 |
hex | 809a4895e1ae |
141400131101102 has 4 divisors (see below), whose sum is σ = 212100196651656. Its totient is φ = 70700065550550.
The previous prime is 141400131101093. The next prime is 141400131101107. The reversal of 141400131101102 is 201101131004141.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1414001311011022 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141400131101107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35350032775274 + ... + 35350032775277.
It is an arithmetic number, because the mean of its divisors is an integer number (53025049162914).
Almost surely, 2141400131101102 is an apocalyptic number.
141400131101102 is a deficient number, since it is larger than the sum of its proper divisors (70700065550554).
141400131101102 is an equidigital number, since it uses as much as digits as its factorization.
141400131101102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70700065550553.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 141400131101102 its reverse (201101131004141), we get a palindrome (342501262105243).
The spelling of 141400131101102 in words is "one hundred forty-one trillion, four hundred billion, one hundred thirty-one million, one hundred one thousand, one hundred two".
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