141400301320037 has 2 divisors, whose sum is σ = 141400301320038. Its totient is φ = 141400301320036.

The previous prime is 141400301319989. The next prime is 141400301320063. The reversal of 141400301320037 is 730023103004141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113395365423076 + 28004935896961 = 10648726^2 + 5291969^2 .

It is an emirp because it is prime and its reverse (730023103004141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141400301320037 - 2⁶ = 141400301319973 is a prime.

It is a super-3 number, since 3×141400301320037³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141400301319991 and 141400301320009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141400301320637) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70700150660018 + 70700150660019.

It is an arithmetic number, because the mean of its divisors is an integer number (70700150660019).

Almost surely, 2^{141400301320037} is an apocalyptic number.

It is an amenable number.

141400301320037 is a deficient number, since it is larger than the sum of its proper divisors (1).

141400301320037 is an equidigital number, since it uses as much as digits as its factorization.

141400301320037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 141400301320037 its reverse (730023103004141), we get a palindrome (871423404324178).

The spelling of 141400301320037 in words is "one hundred forty-one trillion, four hundred billion, three hundred one million, three hundred twenty thousand, thirty-seven".