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141401411 is a prime number
BaseRepresentation
bin10000110110110…
…01110101000011
3100212001221021022
420123121311003
5242144321121
622010420055
73334615004
oct1033316503
9325057238
10141401411
11728a9a78
123b43162b
13233ab198
1414acb1ab
15c631aab
hex86d9d43

141401411 has 2 divisors, whose sum is σ = 141401412. Its totient is φ = 141401410.

The previous prime is 141401371. The next prime is 141401417. The reversal of 141401411 is 114104141.

141401411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141401411 - 222 = 137207107 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141401411.

It is not a weakly prime, because it can be changed into another prime (141401417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70700705 + 70700706.

It is an arithmetic number, because the mean of its divisors is an integer number (70700706).

Almost surely, 2141401411 is an apocalyptic number.

141401411 is a deficient number, since it is larger than the sum of its proper divisors (1).

141401411 is an equidigital number, since it uses as much as digits as its factorization.

141401411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 141401411 is about 11891.2325265298. The cubic root of 141401411 is about 520.9762368463.

Adding to 141401411 its reverse (114104141), we get a palindrome (255505552).

It can be divided in two parts, 14140 and 1411, that added together give a palindrome (15551).

The spelling of 141401411 in words is "one hundred forty-one million, four hundred one thousand, four hundred eleven".