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1414022224117 is a prime number
BaseRepresentation
bin10100100100111010010…
…010101101100011110101
312000011211122021120210211
4110210322102231203311
5141131404142132432
63001332015345421
7204105534406636
oct24447222554365
95004748246724
101414022224117
114a5757755868
121aa069222271
13a34599c75c9
144c620a2988d
1526bae1d2d47
hex1493a4ad8f5

1414022224117 has 2 divisors, whose sum is σ = 1414022224118. Its totient is φ = 1414022224116.

The previous prime is 1414022224063. The next prime is 1414022224129. The reversal of 1414022224117 is 7114222204141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1389590658481 + 24431565636 = 1178809^2 + 156306^2 .

It is a cyclic number.

It is not a de Polignac number, because 1414022224117 - 215 = 1414022191349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1414022224187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707011112058 + 707011112059.

It is an arithmetic number, because the mean of its divisors is an integer number (707011112059).

Almost surely, 21414022224117 is an apocalyptic number.

It is an amenable number.

1414022224117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414022224117 is an equidigital number, since it uses as much as digits as its factorization.

1414022224117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7168, while the sum is 31.

Adding to 1414022224117 its reverse (7114222204141), we get a palindrome (8528244428258).

The spelling of 1414022224117 in words is "one trillion, four hundred fourteen billion, twenty-two million, two hundred twenty-four thousand, one hundred seventeen".