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1414031203033 is a prime number
BaseRepresentation
bin10100100100111010110…
…100111101101011011001
312000011212021011202120021
4110210322310331223121
5141131413441444113
63001332540030441
7204106003624351
oct24447264755331
95004767152507
101414031203033
114a5761828859
121aa070232421
13a345b81c487
144c621cc5b61
1526baeda848d
hex1493ad3dad9

1414031203033 has 2 divisors, whose sum is σ = 1414031203034. Its totient is φ = 1414031203032.

The previous prime is 1414031203021. The next prime is 1414031203141. The reversal of 1414031203033 is 3303021304141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1267274787289 + 146756415744 = 1125733^2 + 383088^2 .

It is a cyclic number.

It is not a de Polignac number, because 1414031203033 - 25 = 1414031203001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1414031202989 and 1414031203007.

It is not a weakly prime, because it can be changed into another prime (1414031203433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707015601516 + 707015601517.

It is an arithmetic number, because the mean of its divisors is an integer number (707015601517).

Almost surely, 21414031203033 is an apocalyptic number.

It is an amenable number.

1414031203033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414031203033 is an equidigital number, since it uses as much as digits as its factorization.

1414031203033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1414031203033 its reverse (3303021304141), we get a palindrome (4717052507174).

The spelling of 1414031203033 in words is "one trillion, four hundred fourteen billion, thirty-one million, two hundred three thousand, thirty-three".