Base | Representation |
---|---|
bin | 10100100100111111100… |
… | …010000100000010101111 |
3 | 12000012001202200220002222 |
4 | 110210333202010002233 |
5 | 141132044143300242 |
6 | 3001344435505555 |
7 | 204110652550163 |
oct | 24447742040257 |
9 | 5005052626088 |
10 | 1414110134447 |
11 | 4a57a233a12a |
12 | 1aa0927582bb |
13 | a3471c9735a |
14 | 4c62c590ca3 |
15 | 26bb6c9a5d2 |
hex | 1493f8840af |
1414110134447 has 2 divisors, whose sum is σ = 1414110134448. Its totient is φ = 1414110134446.
The previous prime is 1414110134413. The next prime is 1414110134461. The reversal of 1414110134447 is 7444310114141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1414110134447 - 212 = 1414110130351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1414110134497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707055067223 + 707055067224.
It is an arithmetic number, because the mean of its divisors is an integer number (707055067224).
Almost surely, 21414110134447 is an apocalyptic number.
1414110134447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414110134447 is an equidigital number, since it uses as much as digits as its factorization.
1414110134447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 1414110134447 its reverse (7444310114141), we get a palindrome (8858420248588).
The spelling of 1414110134447 in words is "one trillion, four hundred fourteen billion, one hundred ten million, one hundred thirty-four thousand, four hundred forty-seven".
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