1414111050301 has 2 divisors, whose sum is σ = 1414111050302. Its totient is φ = 1414111050300.

The previous prime is 1414111050217. The next prime is 1414111050307. The reversal of 1414111050301 is 1030501114141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1123120931076 + 290990119225 = 1059774^2 + 539435^2 .

It is a cyclic number.

It is not a de Polignac number, because 1414111050301 - 2¹¹ = 1414111048253 is a prime.

It is a super-3 number, since 3×1414111050301³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1414111050307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707055525150 + 707055525151.

It is an arithmetic number, because the mean of its divisors is an integer number (707055525151).

Almost surely, 2^{1414111050301} is an apocalyptic number.

It is an amenable number.

1414111050301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414111050301 is an equidigital number, since it uses as much as digits as its factorization.

1414111050301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 1414111050301 its reverse (1030501114141), we get a palindrome (2444612164442).

The spelling of 1414111050301 in words is "one trillion, four hundred fourteen billion, one hundred eleven million, fifty thousand, three hundred one".