Base | Representation |
---|---|
bin | 10100100101000000010… |
… | …001011100001011000011 |
3 | 12000012002122001212121022 |
4 | 110211000101130023003 |
5 | 141132110333212201 |
6 | 3001350002020055 |
7 | 204111163245014 |
oct | 24450021341303 |
9 | 5005078055538 |
10 | 1414122554051 |
11 | 4a57a9352169 |
12 | 1aa09694762b |
13 | a347472532c |
14 | 4c6300a500b |
15 | 26bb7e0041b |
hex | 1494045c2c3 |
1414122554051 has 2 divisors, whose sum is σ = 1414122554052. Its totient is φ = 1414122554050.
The previous prime is 1414122554021. The next prime is 1414122554081. The reversal of 1414122554051 is 1504552214141.
It is a balanced prime because it is at equal distance from previous prime (1414122554021) and next prime (1414122554081).
It is a cyclic number.
It is not a de Polignac number, because 1414122554051 - 222 = 1414118359747 is a prime.
It is not a weakly prime, because it can be changed into another prime (1414122554021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707061277025 + 707061277026.
It is an arithmetic number, because the mean of its divisors is an integer number (707061277026).
Almost surely, 21414122554051 is an apocalyptic number.
1414122554051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414122554051 is an equidigital number, since it uses as much as digits as its factorization.
1414122554051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32000, while the sum is 35.
Adding to 1414122554051 its reverse (1504552214141), we get a palindrome (2918674768192).
The spelling of 1414122554051 in words is "one trillion, four hundred fourteen billion, one hundred twenty-two million, five hundred fifty-four thousand, fifty-one".
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