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141421124147 is a prime number
BaseRepresentation
bin1000001110110101011…
…0110001101000110011
3111112000212210110120212
42003231112301220303
54304112301433042
6144545025254335
713134355502252
oct2035526615063
9445025713525
10141421124147
1154a815a0806
12234a97943ab
131044a128764
146bb827c799
153a2a88a482
hex20ed5b1a33

141421124147 has 2 divisors, whose sum is σ = 141421124148. Its totient is φ = 141421124146.

The previous prime is 141421124113. The next prime is 141421124161. The reversal of 141421124147 is 741421124141.

141421124147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141421124147 is a prime.

It is not a weakly prime, because it can be changed into another prime (141421124177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70710562073 + 70710562074.

It is an arithmetic number, because the mean of its divisors is an integer number (70710562074).

Almost surely, 2141421124147 is an apocalyptic number.

141421124147 is a deficient number, since it is larger than the sum of its proper divisors (1).

141421124147 is an equidigital number, since it uses as much as digits as its factorization.

141421124147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7168, while the sum is 32.

Adding to 141421124147 its reverse (741421124141), we get a palindrome (882842248288).

The spelling of 141421124147 in words is "one hundred forty-one billion, four hundred twenty-one million, one hundred twenty-four thousand, one hundred forty-seven".