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141423442410401 is a prime number
BaseRepresentation
bin100000001001111110110110…
…000011000011101110100001
3200112201221121212021011122022
4200021332312003003232201
5122014040202224113101
61220441011005551225
741534335512115004
oct4011766603035641
9615657555234568
10141423442410401
1141075388380428
1213a40988875515
1360bb233c46a18
1426ccd0706953b
151153b356eaa1b
hex809fb60c3ba1

141423442410401 has 2 divisors, whose sum is σ = 141423442410402. Its totient is φ = 141423442410400.

The previous prime is 141423442410319. The next prime is 141423442410403. The reversal of 141423442410401 is 104014244324141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141302076573025 + 121365837376 = 11887055^2 + 348376^2 .

It is a cyclic number.

It is not a de Polignac number, because 141423442410401 - 222 = 141423438216097 is a prime.

Together with 141423442410403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (141423442410403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70711721205200 + 70711721205201.

It is an arithmetic number, because the mean of its divisors is an integer number (70711721205201).

Almost surely, 2141423442410401 is an apocalyptic number.

It is an amenable number.

141423442410401 is a deficient number, since it is larger than the sum of its proper divisors (1).

141423442410401 is an equidigital number, since it uses as much as digits as its factorization.

141423442410401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 49152, while the sum is 35.

Adding to 141423442410401 its reverse (104014244324141), we get a palindrome (245437686734542).

The spelling of 141423442410401 in words is "one hundred forty-one trillion, four hundred twenty-three billion, four hundred forty-two million, four hundred ten thousand, four hundred one".