Base | Representation |
---|---|
bin | 10100100101001011000… |
… | …110110010011100001111 |
3 | 12000012120022002002100012 |
4 | 110211023012302130033 |
5 | 141132443400423210 |
6 | 3001420013423435 |
7 | 204115531201556 |
oct | 24451306623417 |
9 | 5005508062305 |
10 | 1414304311055 |
11 | 4a5891a04969 |
12 | 1aa12779ab7b |
13 | a34a3292b5c |
14 | 4c64a298d9d |
15 | 26bc8d54305 |
hex | 1494b1b270f |
1414304311055 has 32 divisors (see below), whose sum is σ = 1796177787264. Its totient is φ = 1066923196416.
The previous prime is 1414304311051. The next prime is 1414304311061. The reversal of 1414304311055 is 5501134034141.
It is a cyclic number.
It is not a de Polignac number, because 1414304311055 - 22 = 1414304311051 is a prime.
It is a super-3 number, since 3×14143043110553 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1414304311051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2620169 + ... + 3113501.
It is an arithmetic number, because the mean of its divisors is an integer number (56130555852).
Almost surely, 21414304311055 is an apocalyptic number.
1414304311055 is a deficient number, since it is larger than the sum of its proper divisors (381873476209).
1414304311055 is a wasteful number, since it uses less digits than its factorization.
1414304311055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 493715.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 1414304311055 its reverse (5501134034141), we get a palindrome (6915438345196).
The spelling of 1414304311055 in words is "one trillion, four hundred fourteen billion, three hundred four million, three hundred eleven thousand, fifty-five".
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