Base | Representation |
---|---|
bin | 11010010101111111… |
… | …10100000010110101 |
3 | 1100111122211011101111 |
4 | 31022333310002311 |
5 | 212431121102432 |
6 | 10255224355021 |
7 | 1010323512214 |
oct | 151277640265 |
9 | 40448734344 |
10 | 14143144117 |
11 | 5aa8488563 |
12 | 28a8615a71 |
13 | 144517a33b |
14 | 9824d907b |
15 | 57b9ab347 |
hex | 34aff40b5 |
14143144117 has 2 divisors, whose sum is σ = 14143144118. Its totient is φ = 14143144116.
The previous prime is 14143144111. The next prime is 14143144151. The reversal of 14143144117 is 71144134141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12239218161 + 1903925956 = 110631^2 + 43634^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14143144117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14143144111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7071572058 + 7071572059.
It is an arithmetic number, because the mean of its divisors is an integer number (7071572059).
Almost surely, 214143144117 is an apocalyptic number.
It is an amenable number.
14143144117 is a deficient number, since it is larger than the sum of its proper divisors (1).
14143144117 is an equidigital number, since it uses as much as digits as its factorization.
14143144117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5376, while the sum is 31.
Adding to 14143144117 its reverse (71144134141), we get a palindrome (85287278258).
The spelling of 14143144117 in words is "fourteen billion, one hundred forty-three million, one hundred forty-four thousand, one hundred seventeen".
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