141432433502551 has 2 divisors, whose sum is σ = 141432433502552. Its totient is φ = 141432433502550.

The previous prime is 141432433502513. The next prime is 141432433502557. The reversal of 141432433502551 is 155205334234141.

141432433502551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (155205334234141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141432433502551 - 2¹¹ = 141432433500503 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141432433502498 and 141432433502507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141432433502557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70716216751275 + 70716216751276.

It is an arithmetic number, because the mean of its divisors is an integer number (70716216751276).

Almost surely, 2^{141432433502551} is an apocalyptic number.

141432433502551 is a deficient number, since it is larger than the sum of its proper divisors (1).

141432433502551 is an equidigital number, since it uses as much as digits as its factorization.

141432433502551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 141432433502551 its reverse (155205334234141), we get a palindrome (296637767736692).

The spelling of 141432433502551 in words is "one hundred forty-one trillion, four hundred thirty-two billion, four hundred thirty-three million, five hundred two thousand, five hundred fifty-one".