141433133112 has 48 divisors (see below), whose sum is σ = 383068427040. Its totient is φ = 47141872128.

The previous prime is 141433133087. The next prime is 141433133117. The reversal of 141433133112 is 211331334141.

141433133112 is a `hidden beast` number, since 1 + 4 + 14 + 331 + 3 + 311 + 2 = 666.

It is a super-2 number, since 2×141433133112² (a number of 23 digits) contains 22 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141433133117) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1732968 + ... + 1812744.

It is an arithmetic number, because the mean of its divisors is an integer number (7980592230).

Almost surely, 2^141433133112 is an apocalyptic number.

141433133112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

141433133112 is an abundant number, since it is smaller than the sum of its proper divisors (241635293928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141433133112 is a wasteful number, since it uses less digits than its factorization.

141433133112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104412 (or 104405 counting only the distinct ones).

The product of its digits is 2592, while the sum is 27.

Adding to 141433133112 its reverse (211331334141), we get a palindrome (352764467253).

The spelling of 141433133112 in words is "one hundred forty-one billion, four hundred thirty-three million, one hundred thirty-three thousand, one hundred twelve".