Base | Representation |
---|---|
bin | 1100110111010000000000… |
… | …1111101101011111111011 |
3 | 1212002002102002021201110002 |
4 | 3031310000033231133323 |
5 | 3323211020321034001 |
6 | 50025205020543215 |
7 | 2656551636352031 |
oct | 315640017553773 |
9 | 55062362251402 |
10 | 14143331424251 |
11 | 4563175967107 |
12 | 17050a50b1b0b |
13 | 7b7930a7b5a3 |
14 | 36c7802d6551 |
15 | 197d7932d46b |
hex | cdd003ed7fb |
14143331424251 has 2 divisors, whose sum is σ = 14143331424252. Its totient is φ = 14143331424250.
The previous prime is 14143331424247. The next prime is 14143331424263. The reversal of 14143331424251 is 15242413334141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14143331424251 - 22 = 14143331424247 is a prime.
It is a super-2 number, since 2×141433314242512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14143331324251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7071665712125 + 7071665712126.
It is an arithmetic number, because the mean of its divisors is an integer number (7071665712126).
Almost surely, 214143331424251 is an apocalyptic number.
14143331424251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14143331424251 is an equidigital number, since it uses as much as digits as its factorization.
14143331424251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 138240, while the sum is 38.
Adding to 14143331424251 its reverse (15242413334141), we get a palindrome (29385744758392).
The spelling of 14143331424251 in words is "fourteen trillion, one hundred forty-three billion, three hundred thirty-one million, four hundred twenty-four thousand, two hundred fifty-one".
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