Base | Representation |
---|---|
bin | 1100110111010011101000… |
… | …0110010010100110011111 |
3 | 1212002011220201122202202210 |
4 | 3031310322012102212133 |
5 | 3323220012310031221 |
6 | 50025445212251503 |
7 | 2656614663402042 |
oct | 315647206224637 |
9 | 55064821582683 |
10 | 14144302033311 |
11 | 456362383605a |
12 | 1705316170b93 |
13 | 7b7a56b97a88 |
14 | 36c833192c59 |
15 | 197dd4656276 |
hex | cdd3a19299f |
14144302033311 has 16 divisors (see below), whose sum is σ = 18948656802816. Its totient is φ = 9384843131136.
The previous prime is 14144302033217. The next prime is 14144302033331. The reversal of 14144302033311 is 11333020344141.
It is not a de Polignac number, because 14144302033311 - 241 = 11945278777759 is a prime.
It is a super-2 number, since 2×141443020333112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14144302033331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12215055 + ... + 13322768.
It is an arithmetic number, because the mean of its divisors is an integer number (1184291050176).
Almost surely, 214144302033311 is an apocalyptic number.
14144302033311 is a deficient number, since it is larger than the sum of its proper divisors (4804354769505).
14144302033311 is a wasteful number, since it uses less digits than its factorization.
14144302033311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25538702.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 14144302033311 its reverse (11333020344141), we get a palindrome (25477322377452).
The spelling of 14144302033311 in words is "fourteen trillion, one hundred forty-four billion, three hundred two million, thirty-three thousand, three hundred eleven".
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