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1414431325201 is a prime number
BaseRepresentation
bin10100100101010010101…
…011010011110000010001
312000012220011002001222211
4110211102223103300101
5141133223404401301
63001440352032121
7204121632615316
oct24452253236021
95005804061884
101414431325201
114a5947677534
121aa162232641
13a34c36a455b
144c65d0bcd0d
1526bd5093051
hex14952ad3c11

1414431325201 has 2 divisors, whose sum is σ = 1414431325202. Its totient is φ = 1414431325200.

The previous prime is 1414431325187. The next prime is 1414431325261. The reversal of 1414431325201 is 1025231344141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1411878650625 + 2552674576 = 1188225^2 + 50524^2 .

It is an emirp because it is prime and its reverse (1025231344141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1414431325201 - 223 = 1414422936593 is a prime.

It is not a weakly prime, because it can be changed into another prime (1414431325261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707215662600 + 707215662601.

It is an arithmetic number, because the mean of its divisors is an integer number (707215662601).

Almost surely, 21414431325201 is an apocalyptic number.

It is an amenable number.

1414431325201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414431325201 is an equidigital number, since it uses as much as digits as its factorization.

1414431325201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1414431325201 its reverse (1025231344141), we get a palindrome (2439662669342).

The spelling of 1414431325201 in words is "one trillion, four hundred fourteen billion, four hundred thirty-one million, three hundred twenty-five thousand, two hundred one".