Base | Representation |
---|---|
bin | 10100100101010010101… |
… | …011010011110000010001 |
3 | 12000012220011002001222211 |
4 | 110211102223103300101 |
5 | 141133223404401301 |
6 | 3001440352032121 |
7 | 204121632615316 |
oct | 24452253236021 |
9 | 5005804061884 |
10 | 1414431325201 |
11 | 4a5947677534 |
12 | 1aa162232641 |
13 | a34c36a455b |
14 | 4c65d0bcd0d |
15 | 26bd5093051 |
hex | 14952ad3c11 |
1414431325201 has 2 divisors, whose sum is σ = 1414431325202. Its totient is φ = 1414431325200.
The previous prime is 1414431325187. The next prime is 1414431325261. The reversal of 1414431325201 is 1025231344141.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1411878650625 + 2552674576 = 1188225^2 + 50524^2 .
It is an emirp because it is prime and its reverse (1025231344141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1414431325201 - 223 = 1414422936593 is a prime.
It is not a weakly prime, because it can be changed into another prime (1414431325261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707215662600 + 707215662601.
It is an arithmetic number, because the mean of its divisors is an integer number (707215662601).
Almost surely, 21414431325201 is an apocalyptic number.
It is an amenable number.
1414431325201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414431325201 is an equidigital number, since it uses as much as digits as its factorization.
1414431325201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1414431325201 its reverse (1025231344141), we get a palindrome (2439662669342).
The spelling of 1414431325201 in words is "one trillion, four hundred fourteen billion, four hundred thirty-one million, three hundred twenty-five thousand, two hundred one".
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