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1414431452113 is a prime number
BaseRepresentation
bin10100100101010010101…
…011110010101111010001
312000012220011022112002021
4110211102223302233101
5141133223422431423
63001440354451441
7204121633654321
oct24452253625721
95005804275067
101414431452113
114a5947753919
121aa162293b81
13a34c371a254
144c65d113281
1526bd50ba95d
hex14952af2bd1

1414431452113 has 2 divisors, whose sum is σ = 1414431452114. Its totient is φ = 1414431452112.

The previous prime is 1414431452101. The next prime is 1414431452123. The reversal of 1414431452113 is 3112541344141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 779235204049 + 635196248064 = 882743^2 + 796992^2 .

It is a cyclic number.

It is not a de Polignac number, because 1414431452113 - 237 = 1276992498641 is a prime.

It is not a weakly prime, because it can be changed into another prime (1414431452123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707215726056 + 707215726057.

It is an arithmetic number, because the mean of its divisors is an integer number (707215726057).

Almost surely, 21414431452113 is an apocalyptic number.

It is an amenable number.

1414431452113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414431452113 is an equidigital number, since it uses as much as digits as its factorization.

1414431452113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23040, while the sum is 34.

Adding to 1414431452113 its reverse (3112541344141), we get a palindrome (4526972796254).

The spelling of 1414431452113 in words is "one trillion, four hundred fourteen billion, four hundred thirty-one million, four hundred fifty-two thousand, one hundred thirteen".