Base | Representation |
---|---|
bin | 1100110111010110011010… |
… | …1111110101111110010001 |
3 | 1212002020211221012111110121 |
4 | 3031311212233311332101 |
5 | 3323223031041423401 |
6 | 50030051412030241 |
7 | 2656642360511536 |
oct | 315654657657621 |
9 | 55066757174417 |
10 | 14145051123601 |
11 | 4563978664742 |
12 | 17054a5002381 |
13 | 7b7b46134478 |
14 | 36c8a4868d8d |
15 | 197e2a2c3ca1 |
hex | cdd66bf5f91 |
14145051123601 has 2 divisors, whose sum is σ = 14145051123602. Its totient is φ = 14145051123600.
The previous prime is 14145051123589. The next prime is 14145051123649. The reversal of 14145051123601 is 10632115054141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13318813755025 + 826237368576 = 3649495^2 + 908976^2 .
It is a cyclic number.
It is not a de Polignac number, because 14145051123601 - 27 = 14145051123473 is a prime.
It is not a weakly prime, because it can be changed into another prime (14145051126601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072525561800 + 7072525561801.
It is an arithmetic number, because the mean of its divisors is an integer number (7072525561801).
Almost surely, 214145051123601 is an apocalyptic number.
It is an amenable number.
14145051123601 is a deficient number, since it is larger than the sum of its proper divisors (1).
14145051123601 is an equidigital number, since it uses as much as digits as its factorization.
14145051123601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 14145051123601 its reverse (10632115054141), we get a palindrome (24777166177742).
The spelling of 14145051123601 in words is "fourteen trillion, one hundred forty-five billion, fifty-one million, one hundred twenty-three thousand, six hundred one".
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