Base | Representation |
---|---|
bin | 11010010110011110… |
… | …00111000101001011 |
3 | 1100111221100220020222 |
4 | 31023033013011023 |
5 | 212433132414001 |
6 | 10255450340255 |
7 | 1010402553446 |
oct | 151317070513 |
9 | 40457326228 |
10 | 14147154251 |
11 | 5aaa77741a |
12 | 28a9a2a68b |
13 | 1445c526b9 |
14 | 982c6065d |
15 | 57beee61b |
hex | 34b3c714b |
14147154251 has 2 divisors, whose sum is σ = 14147154252. Its totient is φ = 14147154250.
The previous prime is 14147154239. The next prime is 14147154253. The reversal of 14147154251 is 15245174141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14147154251 - 226 = 14080045387 is a prime.
Together with 14147154253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14147154253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7073577125 + 7073577126.
It is an arithmetic number, because the mean of its divisors is an integer number (7073577126).
Almost surely, 214147154251 is an apocalyptic number.
14147154251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14147154251 is an equidigital number, since it uses as much as digits as its factorization.
14147154251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 22400, while the sum is 35.
The spelling of 14147154251 in words is "fourteen billion, one hundred forty-seven million, one hundred fifty-four thousand, two hundred fifty-one".
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