Base | Representation |
---|---|
bin | 10100100101111100000… |
… | …010101111000000111111 |
3 | 12000021200111222021101111 |
4 | 110211330002233000333 |
5 | 141141134041111111 |
6 | 3002033303022451 |
7 | 204145060565665 |
oct | 24457402570077 |
9 | 5007614867344 |
10 | 1415125332031 |
11 | 4a61733a30a4 |
12 | 1aa31673aa27 |
13 | a35a43c5a98 |
14 | 4c6c7336c35 |
15 | 26c25e7ea21 |
hex | 1497c0af03f |
1415125332031 has 2 divisors, whose sum is σ = 1415125332032. Its totient is φ = 1415125332030.
The previous prime is 1415125331987. The next prime is 1415125332037. The reversal of 1415125332031 is 1302335215141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1415125332031 - 217 = 1415125200959 is a prime.
It is a super-2 number, since 2×14151253320312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1415125331984 and 1415125332002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1415125332037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707562666015 + 707562666016.
It is an arithmetic number, because the mean of its divisors is an integer number (707562666016).
Almost surely, 21415125332031 is an apocalyptic number.
1415125332031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1415125332031 is an equidigital number, since it uses as much as digits as its factorization.
1415125332031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 1415125332031 in words is "one trillion, four hundred fifteen billion, one hundred twenty-five million, three hundred thirty-two thousand, thirty-one".
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