1415143502681 has 2 divisors, whose sum is σ = 1415143502682. Its totient is φ = 1415143502680.

The previous prime is 1415143502623. The next prime is 1415143502683. The reversal of 1415143502681 is 1862053415141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 921377293456 + 493766209225 = 959884^2 + 702685^2 .

It is a cyclic number.

It is not a de Polignac number, because 1415143502681 - 2³⁴ = 1397963633497 is a prime.

It is a super-2 number, since 2×1415143502681² (a number of 25 digits) contains 22 as substring.

Together with 1415143502683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1415143502683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707571751340 + 707571751341.

It is an arithmetic number, because the mean of its divisors is an integer number (707571751341).

Almost surely, 2^{1415143502681} is an apocalyptic number.

It is an amenable number.

1415143502681 is a deficient number, since it is larger than the sum of its proper divisors (1).

1415143502681 is an equidigital number, since it uses as much as digits as its factorization.

1415143502681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 41.

The spelling of 1415143502681 in words is "one trillion, four hundred fifteen billion, one hundred forty-three million, five hundred two thousand, six hundred eighty-one".