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141539187103 is a prime number
BaseRepresentation
bin1000001111010001100…
…1001001100110011111
3111112100002221200111221
42003310121021212133
54304333012441403
6145004443554211
713140321145156
oct2036431114637
9445302850457
10141539187103
11550321aa1a6
122352122b967
1310468724ab2
146bc9c1259d
153a35e0bdbd
hex20f464999f

141539187103 has 2 divisors, whose sum is σ = 141539187104. Its totient is φ = 141539187102.

The previous prime is 141539187071. The next prime is 141539187109. The reversal of 141539187103 is 301781935141.

141539187103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (301781935141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141539187103 - 25 = 141539187071 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141539187103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141539187109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70769593551 + 70769593552.

It is an arithmetic number, because the mean of its divisors is an integer number (70769593552).

Almost surely, 2141539187103 is an apocalyptic number.

141539187103 is a deficient number, since it is larger than the sum of its proper divisors (1).

141539187103 is an equidigital number, since it uses as much as digits as its factorization.

141539187103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 43.

The spelling of 141539187103 in words is "one hundred forty-one billion, five hundred thirty-nine million, one hundred eighty-seven thousand, one hundred three".