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1415501431313 is a prime number
BaseRepresentation
bin10100100110010010011…
…101011100001000010001
312000022122201200002121112
4110212102131130020101
5141142421331300223
63002134500103105
7204160305434234
oct24462235341021
95008581602545
101415501431313
114a6346724052
121aa400694a95
13a36342b9638
144c72127941b
1526c48ec1778
hex1499275c211

1415501431313 has 2 divisors, whose sum is σ = 1415501431314. Its totient is φ = 1415501431312.

The previous prime is 1415501431237. The next prime is 1415501431319. The reversal of 1415501431313 is 3131341055141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1019467837969 + 396033593344 = 1009687^2 + 629312^2 .

It is a cyclic number.

It is not a de Polignac number, because 1415501431313 - 212 = 1415501427217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1415501431313.

It is not a weakly prime, because it can be changed into another prime (1415501431319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707750715656 + 707750715657.

It is an arithmetic number, because the mean of its divisors is an integer number (707750715657).

Almost surely, 21415501431313 is an apocalyptic number.

It is an amenable number.

1415501431313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1415501431313 is an equidigital number, since it uses as much as digits as its factorization.

1415501431313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 32.

Adding to 1415501431313 its reverse (3131341055141), we get a palindrome (4546842486454).

The spelling of 1415501431313 in words is "one trillion, four hundred fifteen billion, five hundred one million, four hundred thirty-one thousand, three hundred thirteen".