Search a number
-
+
141553241113 is a prime number
BaseRepresentation
bin1000001111010100111…
…0110000110000011001
3111112101002101200222211
42003311032300300121
54304400112203423
6145010105115121
713140551461024
oct2036516606031
9445332350884
10141553241113
115503a129189
1223525a88aa1
131046b60598b
146bcba301bb
153a3728610d
hex20f53b0c19

141553241113 has 2 divisors, whose sum is σ = 141553241114. Its totient is φ = 141553241112.

The previous prime is 141553241083. The next prime is 141553241173. The reversal of 141553241113 is 311142355141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131197532944 + 10355708169 = 362212^2 + 101763^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141553241113 is a prime.

It is a super-2 number, since 2×1415532411132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141553241173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70776620556 + 70776620557.

It is an arithmetic number, because the mean of its divisors is an integer number (70776620557).

Almost surely, 2141553241113 is an apocalyptic number.

It is an amenable number.

141553241113 is a deficient number, since it is larger than the sum of its proper divisors (1).

141553241113 is an equidigital number, since it uses as much as digits as its factorization.

141553241113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7200, while the sum is 31.

Adding to 141553241113 its reverse (311142355141), we get a palindrome (452695596254).

The spelling of 141553241113 in words is "one hundred forty-one billion, five hundred fifty-three million, two hundred forty-one thousand, one hundred thirteen".