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141554353117 is a prime number
BaseRepresentation
bin1000001111010101001…
…1000000001111011101
3111112101011111012101011
42003311103000033131
54304400403244432
6145010145015221
713140564102022
oct2036523001735
9445334435334
10141554353117
115503a8186a1
1223526324511
131046b904b78
146bcbc3d549
153a37405847
hex20f54c03dd

141554353117 has 2 divisors, whose sum is σ = 141554353118. Its totient is φ = 141554353116.

The previous prime is 141554353027. The next prime is 141554353123. The reversal of 141554353117 is 711353455141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108544550521 + 33009802596 = 329461^2 + 181686^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141554353117 is a prime.

It is a super-3 number, since 3×1415543531173 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 141554353117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141554353517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70777176558 + 70777176559.

It is an arithmetic number, because the mean of its divisors is an integer number (70777176559).

Almost surely, 2141554353117 is an apocalyptic number.

It is an amenable number.

141554353117 is a deficient number, since it is larger than the sum of its proper divisors (1).

141554353117 is an equidigital number, since it uses as much as digits as its factorization.

141554353117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 126000, while the sum is 40.

The spelling of 141554353117 in words is "one hundred forty-one billion, five hundred fifty-four million, three hundred fifty-three thousand, one hundred seventeen".