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14159252407477 is a prime number
BaseRepresentation
bin1100111000001011010100…
…1101011100010010110101
31212010121111122102110121111
43032002311031130102311
53323441122104014402
650040400514515021
72660654321442532
oct316026515342265
955117448373544
1014159252407477
1145699a5942491
1217081a8b95a71
137b929a359b18
1436d450979d89
151984abe169d7
hexce0b535c4b5

14159252407477 has 2 divisors, whose sum is σ = 14159252407478. Its totient is φ = 14159252407476.

The previous prime is 14159252407471. The next prime is 14159252407541. The reversal of 14159252407477 is 77470425295141.

14159252407477 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13656232448356 + 503019959121 = 3695434^2 + 709239^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14159252407477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14159252407471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7079626203738 + 7079626203739.

It is an arithmetic number, because the mean of its divisors is an integer number (7079626203739).

Almost surely, 214159252407477 is an apocalyptic number.

It is an amenable number.

14159252407477 is a deficient number, since it is larger than the sum of its proper divisors (1).

14159252407477 is an equidigital number, since it uses as much as digits as its factorization.

14159252407477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19756800, while the sum is 58.

The spelling of 14159252407477 in words is "fourteen trillion, one hundred fifty-nine billion, two hundred fifty-two million, four hundred seven thousand, four hundred seventy-seven".