14165120173 has 2 divisors, whose sum is σ = 14165120174. Its totient is φ = 14165120172.

The previous prime is 14165120159. The next prime is 14165120227. The reversal of 14165120173 is 37102156141.

14165120173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13488964164 + 676156009 = 116142^2 + 26003^2 .

It is a cyclic number.

It is not a de Polignac number, because 14165120173 - 2¹³ = 14165111981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14165120113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7082560086 + 7082560087.

It is an arithmetic number, because the mean of its divisors is an integer number (7082560087).

Almost surely, 2^14165120173 is an apocalyptic number.

It is an amenable number.

14165120173 is a deficient number, since it is larger than the sum of its proper divisors (1).

14165120173 is an equidigital number, since it uses as much as digits as its factorization.

14165120173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

The spelling of 14165120173 in words is "fourteen billion, one hundred sixty-five million, one hundred twenty thousand, one hundred seventy-three".