1416605511281 has 2 divisors, whose sum is σ = 1416605511282. Its totient is φ = 1416605511280.

The previous prime is 1416605511263. The next prime is 1416605511283. The reversal of 1416605511281 is 1821155066141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1225413576256 + 191191935025 = 1106984^2 + 437255^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1416605511281 is a prime.

It is a super-2 number, since 2×1416605511281² (a number of 25 digits) contains 22 as substring.

Together with 1416605511283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1416605511283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 708302755640 + 708302755641.

It is an arithmetic number, because the mean of its divisors is an integer number (708302755641).

Almost surely, 2^{1416605511281} is an apocalyptic number.

It is an amenable number.

1416605511281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1416605511281 is an equidigital number, since it uses as much as digits as its factorization.

1416605511281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 41.

The spelling of 1416605511281 in words is "one trillion, four hundred sixteen billion, six hundred five million, five hundred eleven thousand, two hundred eighty-one".