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14166233551 is a prime number
BaseRepresentation
bin11010011000101111…
…11001000111001111
31100120021021020010201
431030113321013033
5213003023433201
610301411314331
71011023666311
oct151427710717
940507236121
1014166233551
11600a518a38
1228b42ab9a7
131449ba2a22
149855c97b1
1557da1c801
hex34c5f91cf

14166233551 has 2 divisors, whose sum is σ = 14166233552. Its totient is φ = 14166233550.

The previous prime is 14166233509. The next prime is 14166233563. The reversal of 14166233551 is 15533266141.

It is a strong prime.

It is an emirp because it is prime and its reverse (15533266141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14166233551 - 211 = 14166231503 is a prime.

It is a super-3 number, since 3×141662335513 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14166233551.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14166203551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7083116775 + 7083116776.

It is an arithmetic number, because the mean of its divisors is an integer number (7083116776).

Almost surely, 214166233551 is an apocalyptic number.

14166233551 is a deficient number, since it is larger than the sum of its proper divisors (1).

14166233551 is an equidigital number, since it uses as much as digits as its factorization.

14166233551 is an evil number, because the sum of its binary digits is even.

The product of its digits is 64800, while the sum is 37.

Adding to 14166233551 its reverse (15533266141), we get a palindrome (29699499692).

The spelling of 14166233551 in words is "fourteen billion, one hundred sixty-six million, two hundred thirty-three thousand, five hundred fifty-one".