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14171125603 is a prime number
BaseRepresentation
bin11010011001010101…
…00011011101100011
31100120121110202202211
431030222203131203
5213010302004403
610302104222551
71011113402665
oct151452433543
940517422684
1014171125603
11601225a458
1228b5a6aa57
13144abc662b
14986100535
1557e18706d
hex34caa3763

14171125603 has 2 divisors, whose sum is σ = 14171125604. Its totient is φ = 14171125602.

The previous prime is 14171125597. The next prime is 14171125609. The reversal of 14171125603 is 30652117141.

It is a balanced prime because it is at equal distance from previous prime (14171125597) and next prime (14171125609).

It is an emirp because it is prime and its reverse (30652117141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14171125603 - 225 = 14137571171 is a prime.

It is a super-2 number, since 2×141711256032 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14171125609) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7085562801 + 7085562802.

It is an arithmetic number, because the mean of its divisors is an integer number (7085562802).

Almost surely, 214171125603 is an apocalyptic number.

14171125603 is a deficient number, since it is larger than the sum of its proper divisors (1).

14171125603 is an equidigital number, since it uses as much as digits as its factorization.

14171125603 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 31.

The spelling of 14171125603 in words is "fourteen billion, one hundred seventy-one million, one hundred twenty-five thousand, six hundred three".