Base | Representation |
---|---|
bin | 10100100111111010110… |
… | …000001000010001110011 |
3 | 12000111011200002120210021 |
4 | 110213322300020101303 |
5 | 141210012244124303 |
6 | 3003024242544311 |
7 | 204251543050453 |
oct | 24477260102163 |
9 | 5014150076707 |
10 | 1417251161203 |
11 | 4a7064373009 |
12 | 1aa80a668097 |
13 | a3852958377 |
14 | 4c8497c7d63 |
15 | 26cec8e9ebd |
hex | 149fac08473 |
1417251161203 has 2 divisors, whose sum is σ = 1417251161204. Its totient is φ = 1417251161202.
The previous prime is 1417251161189. The next prime is 1417251161321. The reversal of 1417251161203 is 3021611527141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1417251161203 - 233 = 1408661226611 is a prime.
It is not a weakly prime, because it can be changed into another prime (1417251161003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 708625580601 + 708625580602.
It is an arithmetic number, because the mean of its divisors is an integer number (708625580602).
Almost surely, 21417251161203 is an apocalyptic number.
1417251161203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1417251161203 is an equidigital number, since it uses as much as digits as its factorization.
1417251161203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 34.
Adding to 1417251161203 its reverse (3021611527141), we get a palindrome (4438862688344).
The spelling of 1417251161203 in words is "one trillion, four hundred seventeen billion, two hundred fifty-one million, one hundred sixty-one thousand, two hundred three".
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