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1418119468133 is a prime number
BaseRepresentation
bin10100101000101110100…
…000011101010001100101
312000120102011222010222012
4110220232200131101211
5141213302040440013
63003250341444005
7204312215406524
oct24505640352145
95016364863865
101418119468133
114a746a518945
121aaa11410605
13a3960806254
144c8ccc544bb
1526d4dc661a8
hex14a2e81d465

1418119468133 has 2 divisors, whose sum is σ = 1418119468134. Its totient is φ = 1418119468132.

The previous prime is 1418119468121. The next prime is 1418119468169. The reversal of 1418119468133 is 3318649118141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1174954106209 + 243165361924 = 1083953^2 + 493118^2 .

It is a cyclic number.

It is not a de Polignac number, because 1418119468133 - 212 = 1418119464037 is a prime.

It is a super-2 number, since 2×14181194681332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1418119461133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 709059734066 + 709059734067.

It is an arithmetic number, because the mean of its divisors is an integer number (709059734067).

Almost surely, 21418119468133 is an apocalyptic number.

It is an amenable number.

1418119468133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1418119468133 is an equidigital number, since it uses as much as digits as its factorization.

1418119468133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 497664, while the sum is 50.

The spelling of 1418119468133 in words is "one trillion, four hundred eighteen billion, one hundred nineteen million, four hundred sixty-eight thousand, one hundred thirty-three".