Base | Representation |
---|---|
bin | 101010010000111… |
… | …0010100010111101 |
3 | 10122211111011202101 |
4 | 1110201302202331 |
5 | 10401021101213 |
6 | 352415425101 |
7 | 50100011263 |
oct | 12441624275 |
9 | 3584434671 |
10 | 1418143933 |
11 | 668561588 |
12 | 336b25191 |
13 | 197a6212b |
14 | d64b6433 |
15 | 8477abdd |
hex | 548728bd |
1418143933 has 2 divisors, whose sum is σ = 1418143934. Its totient is φ = 1418143932.
The previous prime is 1418143919. The next prime is 1418143943. The reversal of 1418143933 is 3393418141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1168409124 + 249734809 = 34182^2 + 15803^2 .
It is a cyclic number.
It is not a de Polignac number, because 1418143933 - 229 = 881273021 is a prime.
It is a super-2 number, since 2×14181439332 = 4022264429409416978, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1418143892 and 1418143901.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1418143943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 709071966 + 709071967.
It is an arithmetic number, because the mean of its divisors is an integer number (709071967).
Almost surely, 21418143933 is an apocalyptic number.
It is an amenable number.
1418143933 is a deficient number, since it is larger than the sum of its proper divisors (1).
1418143933 is an equidigital number, since it uses as much as digits as its factorization.
1418143933 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 37.
The square root of 1418143933 is about 37658.2518579926. The cubic root of 1418143933 is about 1123.5009322284.
The spelling of 1418143933 in words is "one billion, four hundred eighteen million, one hundred forty-three thousand, nine hundred thirty-three".
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