Base | Representation |
---|---|
bin | 1100111010100100100111… |
… | …1111110001000001010011 |
3 | 1212021112201112011002101201 |
4 | 3032221021333301001103 |
5 | 3330124411223130303 |
6 | 50111324130012031 |
7 | 2663642142521113 |
oct | 316511177610123 |
9 | 55245645132351 |
10 | 14200403333203 |
11 | 45853a252900a |
12 | 1714172417017 |
13 | 7c01279b0909 |
14 | 371435d41043 |
15 | 1995b999381d |
hex | cea49ff1053 |
14200403333203 has 2 divisors, whose sum is σ = 14200403333204. Its totient is φ = 14200403333202.
The previous prime is 14200403333191. The next prime is 14200403333209. The reversal of 14200403333203 is 30233330400241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14200403333203 - 217 = 14200403202131 is a prime.
It is not a weakly prime, because it can be changed into another prime (14200403333209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7100201666601 + 7100201666602.
It is an arithmetic number, because the mean of its divisors is an integer number (7100201666602).
Almost surely, 214200403333203 is an apocalyptic number.
14200403333203 is a deficient number, since it is larger than the sum of its proper divisors (1).
14200403333203 is an equidigital number, since it uses as much as digits as its factorization.
14200403333203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 14200403333203 its reverse (30233330400241), we get a palindrome (44433733733444).
The spelling of 14200403333203 in words is "fourteen trillion, two hundred billion, four hundred three million, three hundred thirty-three thousand, two hundred three".
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