Base | Representation |
---|---|
bin | 100000010010011011100111… |
… | …111100111010001010100101 |
3 | 200121210110101220102101010002 |
4 | 200102123213330322022211 |
5 | 122103043344130303013 |
6 | 1222003441050311045 |
7 | 41624312661220511 |
oct | 4022334774721245 |
9 | 617713356371102 |
10 | 142004100244133 |
11 | 41279667604146 |
12 | 13b15419a28485 |
13 | 6130c1059411a |
14 | 270d06c547141 |
15 | 1163cbc441358 |
hex | 8126e7f3a2a5 |
142004100244133 has 2 divisors, whose sum is σ = 142004100244134. Its totient is φ = 142004100244132.
The previous prime is 142004100244063. The next prime is 142004100244211. The reversal of 142004100244133 is 331442001400241.
142004100244133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86498053987489 + 55506046256644 = 9300433^2 + 7450238^2 .
It is a cyclic number.
It is not a de Polignac number, because 142004100244133 - 232 = 141999805276837 is a prime.
It is a super-2 number, since 2×1420041002441332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 142004100244096 and 142004100244105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142004100244733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71002050122066 + 71002050122067.
It is an arithmetic number, because the mean of its divisors is an integer number (71002050122067).
Almost surely, 2142004100244133 is an apocalyptic number.
It is an amenable number.
142004100244133 is a deficient number, since it is larger than the sum of its proper divisors (1).
142004100244133 is an equidigital number, since it uses as much as digits as its factorization.
142004100244133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 142004100244133 its reverse (331442001400241), we get a palindrome (473446101644374).
The spelling of 142004100244133 in words is "one hundred forty-two trillion, four billion, one hundred million, two hundred forty-four thousand, one hundred thirty-three".
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