Base | Representation |
---|---|
bin | 10100101010100101001… |
… | …011011010011100101101 |
3 | 12000202112221100000020202 |
4 | 110222211023122130231 |
5 | 141231341233041422 |
6 | 3004220103123245 |
7 | 204412442401106 |
oct | 24524513323455 |
9 | 5022487300222 |
10 | 1420110440237 |
11 | 4a82a1359735 |
12 | 1ab288143525 |
13 | a3bba13c358 |
14 | 4ca3b43d3ad |
15 | 26e18943b92 |
hex | 14aa52da72d |
1420110440237 has 2 divisors, whose sum is σ = 1420110440238. Its totient is φ = 1420110440236.
The previous prime is 1420110440201. The next prime is 1420110440251. The reversal of 1420110440237 is 7320440110241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 803298120361 + 616812319876 = 896269^2 + 785374^2 .
It is a cyclic number.
It is not a de Polignac number, because 1420110440237 - 212 = 1420110436141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1420110440257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710055220118 + 710055220119.
It is an arithmetic number, because the mean of its divisors is an integer number (710055220119).
Almost surely, 21420110440237 is an apocalyptic number.
It is an amenable number.
1420110440237 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420110440237 is an equidigital number, since it uses as much as digits as its factorization.
1420110440237 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 29.
Adding to 1420110440237 its reverse (7320440110241), we get a palindrome (8740550550478).
The spelling of 1420110440237 in words is "one trillion, four hundred twenty billion, one hundred ten million, four hundred forty thousand, two hundred thirty-seven".
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