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1420110440237 is a prime number
BaseRepresentation
bin10100101010100101001…
…011011010011100101101
312000202112221100000020202
4110222211023122130231
5141231341233041422
63004220103123245
7204412442401106
oct24524513323455
95022487300222
101420110440237
114a82a1359735
121ab288143525
13a3bba13c358
144ca3b43d3ad
1526e18943b92
hex14aa52da72d

1420110440237 has 2 divisors, whose sum is σ = 1420110440238. Its totient is φ = 1420110440236.

The previous prime is 1420110440201. The next prime is 1420110440251. The reversal of 1420110440237 is 7320440110241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 803298120361 + 616812319876 = 896269^2 + 785374^2 .

It is a cyclic number.

It is not a de Polignac number, because 1420110440237 - 212 = 1420110436141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1420110440257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710055220118 + 710055220119.

It is an arithmetic number, because the mean of its divisors is an integer number (710055220119).

Almost surely, 21420110440237 is an apocalyptic number.

It is an amenable number.

1420110440237 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420110440237 is an equidigital number, since it uses as much as digits as its factorization.

1420110440237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 1420110440237 its reverse (7320440110241), we get a palindrome (8740550550478).

The spelling of 1420110440237 in words is "one trillion, four hundred twenty billion, one hundred ten million, four hundred forty thousand, two hundred thirty-seven".